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Sav [38]
3 years ago
13

If f(x) = 1 – x, which value is equivalent to |f(i)|? 0 1 √2 √-1

Mathematics
1 answer:
Sedaia [141]3 years ago
8 0

Answer:

\sqrt{2}


Step-by-step explanation:

We plug in i into f(x) to get:

f(i)=1-i


<em>Here, i is the imaginary number i=\sqrt{-1}</em>

To get absolute value of an imaginary number, we use the following formula:

a+bi=\sqrt{a^2+b^2}


So absolute value of f(i) is:

|f(i)|=\sqrt{(1)^2+(1)^2} \\=\sqrt{1+1} \\=\sqrt{2}

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Step-by-step explanation:

Let the number of two point goals = x

Let the number of three point goals = y

Let the number of free throws = z

As per the given statements:

x = 2y-77 ...... (1)

z = x-30 ...... (2)

Using equation (1):

z = 2y-107 ...... (3)

Total number of points from two point goals  = 2x

Total number of points from three point goals  = 3y

Total number of points from free throws  = z

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Number of three point goals = 123

Number of free throws = 139

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