Answer: Parallel: y=-2/7x-2 1/7 Perpendicular: y=7/2x+13
Step-by-step explanation:
2x+7y=14
Subtract 2x from both sides.
7y=-2x+14
Divide both sides by 7 to isolate y.
y=-2/7x+2
Parallel:
Plug in x and y with same slope as the original.
-1=-2/7(-4)+b
Solve for b:
-1=8/7+b
-2 1/7=b
y=-2/7x-2 1/7
Perpendicular:
Plug in x and y with the negative inverse of the original slope.
-1=7/2(-4)+b
Solve for b.
-1=-28/2+b
-1=-14+b
13=b
y=7/2x+13
The range of the function is the y-component or the ordinate of the sets of points. The domain of the function meanwhile is the x-component ot the abscissa of the sets of points. In this case, we have the function <span>f(x) = 4x – 3 and given each y, we get the x. Subsituting each y to the function we get the domain equal to {3.535, 4.5, 5, 8}.</span>
An interval graph in graphical theory is indeed an undirected graph formed by an interval set just on true line, with a top for every interval as well as an edge between vertex v to intersections. Graph intervals and these graphs are chordal graphs and graphs that are perfect, and the further discussion can be defined as follows:
Given:
![\bold{Interval \ \[-6, 3\]}](https://tex.z-dn.net/?f=%5Cbold%7BInterval%20%5C%20%5C%5B-6%2C%203%5C%5D%7D)
To find:
Domain=?
Solution:
The is a graphic over the![[-6,3]](https://tex.z-dn.net/?f=%5B-6%2C3%5D)
interval.
A<em><u> graph of the domain</u></em> ![[-3,6 ]](https://tex.z-dn.net/?f=%5B-3%2C6%20%5D)
is indicated mostly by the <em><u>transformation </u></em>that <em><u>horizontal shifts</u></em> to combat 
.
=|x-3|
Therefore, the final answer is "Option (D)".
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F(x) = 3x-6
g(x) = x-2
so f/g = 3(x-2)/(x-2) = 3
hope this will help you
The length of a circumference: l=πD
l₁=π×5=5π
l₂=π×15=15π
Then l₂÷l₁=15π÷5π=3 and the answer is B)
