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Margarita [4]
3 years ago
15

When solid (NH4)(NH2CO2)(NH4)(NH2CO2) is introduced into an evacuated flask at 25 ∘C∘C, the total pressure of gas at equilibrium

is 0.116 atmatm. What is the value of KpKp at 25 ∘C∘C?
Chemistry
1 answer:
USPshnik [31]3 years ago
7 0

Answer:

the value of Kp at 25°C is 2.37 × 10⁻⁴atm³

Explanation:

Given that Kp = 0.116atm

NH₄(NH₂CO₂)(s) ⇄ 2NH₃(g) + CO₂(g)

                               2x atm         xatm

Pt                     =      PNH₃         PCO₂

0.116                =      2x          +        x

0.116                =      3x

x = 0.116/3

x = 0.039 atm

PNH₃ = 2x =2(0.039) = 0.078 atm

PCO₂ = x = 0.039 atm

Now,

KP = PNH₃² × PCO₂

     = 0.078² × 0.039 atm³

     = 2.37  × 10⁻⁴ atm³

the value of Kp at 25°C is 2.37 × 10⁻⁴atm³

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In yeast, ethanol is produced from glucose under anaerobic conditions. A cell‑free yeast extract is placed in a solution that co
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650 mmol.

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Since NAD⁺/NADH is used and regenerated, we can eliminate it from the equation:

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3 years ago
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<u>Answer:</u> The number of atoms of carbon present in given number of moles are 2.350\times 10^{20}

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So, 3.900\times 10^{-4}mol of carbon will contain = 3.900\times 10^{-4}\times 6.022\times 10^{23}=2.350\times 10^{20} number of atoms.

Hence, the number of atoms of carbon present in given number of moles are 2.350\times 10^{20}

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