Let's write the reaction first:
<span>2 Au + 2 BrF</span>₃<span> + 2 KF → 2 KAuF</span>₄<span> + Br</span>₂<span>
</span>
To know which of the substances is the oxidizing agent, calculate the oxidation numbers of each element before and after the reaction. If the element's oxidation number decreases, then that is the oxidation agent. Let's calculate Br.
BrF₃: x + 3(-1) = 0; x = +3
Br₂: 0 (for any elemental form, oxidation number is 0)
The oxidation number is reduced from +3 to 0. <em>Thus, BrF₃ is the oxidizing agent.</em>
Mg 10.9g/24.31=0.018/0.018=1
Cl 31.8g/35.45=0.897/0.018=49.83=50
O 57.3g/16.00=3.581/0.018=198.94=199
empirical formula=MgCl50O199
I think it's right
44.8% oxygen, 21.5% silicon, and 22.8% magnesium. There's also iron, aluminum, calcium, sodium, and potassium. These elements are all bound together in the form of silicate rocks, all of which take the form of oxides.
