An electromagent is being shown. Because the picture is showing how to put the lightnulb in and where it is
Fill in the blanks in order w/ these numbers:
1. 2 1 2 1
2. 3 1 1
3. 1 2 1 2
4. 2 1 1
5. 4 3 2
6. 1 1 2
Hope this helps.
Answer:
5. +5
6. +7
Explanation:
The oxidation state can be obtained as follow:
5. Oxidation state of oxygen, O = –2
Oxidation state of phosphorus, P =?
P3O10 = –5
3P + 10O = –5
3P + (10 x –2) = –5
3P – 20 = –5
Collect like terms
3P = –5 + 20
3P = 15
Divide both side by 3
P = 15/3
P = +5
Therefore, the oxidation state of P in P3O10^5- is +5
6. Oxidation state of oxygen, O = –2
Oxidation state of manganese, Mn =.?
Mn2O7 = 0
2Mn + 7O = 0
2Mn + (7 x –2) = 0
2Mn – 14 = 0
Collect like terms
2Mn = 14
Divide both side by 2
Mn = 14/2
Mn = +7
Therefore, the oxidation state of Mn in Mn2O7 is +7
Answer:
A(yellow) = 52
Explanation:
A(yellow) = A(total) - A(red)
= 11×6 - 7×2
= 66 - 14
= 52
