Evaluate x(y+3)/(3+y)z for x=6 y=9 z=2

Mathematics

2 answers:

GrogVix [38]3 years ago

8 0

I got 72/24 because I swapped out the variables with the numbers and continued with distributive property

Ksenya-84 [330]3 years ago

3 0

Answer:3

Step-by-step explanation:plug in the numbers in the algebraic expression. Should look like this: 6(9+3)/(3+9)2. After you set it up like this you have to get rid of the parentheses by multiplying the outside number to the numbers in the parentheses. So do: 6×9=54, then 6×3=18 so now your problem should look like this 54+18/ (3+9)2 do the same with the other side so: 2×3=6, then 9×2=18 now your problem should look like this: 54+18/6+18 now you add each side up 54+18=72 and 6+18=24 . Then divide those 2 answers which looks like this 72/24 = 3.

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Given the function f\left(x\right)=-3x+6f(x)=−3x+6 with a domain of [-2, 7), identify the range of the function using same notat

Aliun [14]

Answer:

The range of the function is represented by $Ran\{f(x)\} = (-15, 12]$ .

Step-by-step explanation:

Let be $f(x) = -3\cdot x + 6$ , for $x \in [-2,7)$ . As we notice that $f(x)$ is an inyective function, that is, the inexistence of two or more domain element with the same image, with a monotone behavior, we can obtain the bounds of the range of the function by evaluating the expression: