Answer:
(5/24) gallons of gas to mow the side yard
Step-by-step explanation:
We can easily solve this proble by applying a rule of three
5/16 gallons of gas --------------------------------- for 1 backyard
x gallons of gas ------------------------------------- 2/3 backyard
x = ((2/3)/1)*(5/16) gallons of gas
x = ((2/3))*(5/16) gallons of gas
x = ((10/48) gallons of gas
x = (5/24) gallons of gas
F(x) = 2x^2 + 5x
f(3b) = 2(3b)^2 + 5(3b) = 2(9b^2) + 15b = 18b^2 + 15b
The answer is 20 because it is 4 more after 16
Answer:
EndRoot Over 2 EndFraction
StartFraction pi Over 6 EndFraction, StartFraction StartRoot 3 EndRoot Over 2 EndFraction