We know that the Circumcenter is the intersection of a triangle's right (perpendicular) bisectors. Once you have found two of these you can determine their point of intersection.
It is a proven mathematical concept that the third perpendicular bisector will also cross through this intersection point. While it is not necessary to construct all three it is often done so to verify that the intersection of the first two perpendicular bisectors was in fact correct.
the answer is A ,when x=0,g(x)is-1,so when u add x into the g(x),which is given below,u can find C,D,E,g(x) is no equal to -1,when you add x=1 into g(x)(A,B),you can find g(x) of B is 0,which is no equal the answer giving above(g(x)=2),but A is all right.
The answer would be D. 18/6. We can figure this out because in the question, it says that each shape is worth one whole. There are three shapes so that means when added, the sum is 3 and 18/6, when reduced is 3.
I hope this helped! :-)
