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Natasha_Volkova [10]
3 years ago
6

Please see answerrrrr

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
6 0

Answer: 1. 8/35      2. 11/35

Step-by-step explanation:

1.  If the first expression you have to solve the parentheses first the multiply is by 2/7  

so \frac{1}{5} + \frac{3}{5}   = 4/5

\frac{4}{5} * \frac{2}{7} = \frac{8}{35}    

2.  You have to multiply first before you add in the second one using the rules of pemdas.

3/5 * 2/7 = 6 / 35

Now add 6/35 and 1/5

\frac{1}{5} + \frac{6}{35}  To add them they have to have the same denominators so we will multiply 5 by 7 to get 35 and  the same as the top one.

\frac{7}{35} +\frac{6}{35} = 13/35  

Hitman42 [59]3 years ago
3 0

Answer:

1. 8/35

2. 13/35

Explanation:

You add the numbers in the parentheses first, then you multiply

1. 1/5 + 3/5 = 4/5

4/5 * 2/7 = 8/35

———————————

2. 1/5 + 3/5 * 2/7

You would multiply 3/5 and 2/7 first

1/5 + 6/35

Then you find a common denominator

1/5 = 7/35

Then you add 7/35 and 6/35

7/35 + 6/35 = 13/35

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Anna71 [15]

Answer:

The pairs of integer having two real solution forax^{2} -6x+c = 0 are

  1. a = -4, c = 5
  2. a = 1, c = 6
  3. a = 2, c = 3
  4. a = 3, c = 3

Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

1x^{2} -6x+6 = 0 for a = 1 , c=6

2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

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Step-by-step explanation:

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Answer:

-1/5

Step-by-step explanation:

8/15 - 11/15

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