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3 years ago

24.H T (Simplify):(a - b)² + 4ab. (a+b(a + b)² - 4abla-ba-b?(a + b)2)

Mathematics

1 answer:

damaskus [11]3 years ago

8 0

Answer: hahahaha you really thought i was going to give u the answer learn from your teacher stop cheating.

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Find the equation for the circle with center (4,3) and passing through (2,-4)

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Answer:

$(x - 4)^{2} + (y - 3)^{2} = 53$

Step-by-step explanation:

The general equation of a circle is as follows:

$(x - x_{c})^{2} + (y - y_{c})^{2} = r^{2}$

In which the center is $(x_{c}, y_{c})$ , and r is the radius.

In this problem, we have that:

$x_{c} = 4, y_{c} = 3$

$(x - 4)^{2} + (y - 3)^{2} = r^{2}$

Passing through (2,-4)

We replace into the equation to find the radius.

$(2 - 4)^{2} + (-4 - 3)^{2} = r^{2}$

$4 + 49 = r^{2}$

$r^{2} = 53$

The equation of the circle is:

$(x - 4)^{2} + (y - 3)^{2} = 53$

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24.H T (Simplify):(a - b)² + 4ab. (a+b(a + b)² - 4abla-ba-b?(a + b)2)​

24.H T (Simplify):(a - b)² + 4ab. (a+b(a + b)² - 4abla-ba-b?(a + b)2)