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tino4ka555 [31]
3 years ago
13

Hi, i need to know the work and answer to this. thanks!

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0

Answer:

432 in^2

Step-by-step explanation:

in similar quadrilaterals, the first point of one quad. corresponds to the first point of the other quad, so in this case UA corresponds with CH.

since CH is 3/4 the length of UA, we can also assume that the other sides in ZUCH are 3/4 the length of their corresponding sides in SQUA.

even though we don't know what quadrilateral SQUA and ZUCH are, we know the area of SQUA is 9/16 times less than ZUCH.

want some proof?

lets say SQUA and ZUCH are rectangle/square

ZUCH: 4X4 = 16

SQUA: 3X3 = 9

now lets say they are trapezoids. We will set ZUCH 2nd base to 8 and height to 16, therefore SQUA bases will be 3 and 6, and the height will be 12 (multiply ZUCH lengths by 3/4)

ZUCH = (b1+b2)(h)/2 = (4+8)(16)/2 = 96

SQUA = (b1+b2)(h)/2 = (3+6)(12)/2 = 54

simplify 96/54 = 16/9

now we can multiply 243 by our factor 16/9 to find the area of SQUA.

243 * 16/9 = 432 in^2

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Step-by-step explanation:

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a) 2,350,000,000

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Step-by-step explanation:

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Read 2 more answers
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Leokris [45]
Divide -10 in 15 = -0.666666666
7 0
3 years ago
Read 2 more answers
Please explain every step
pogonyaev
<h3>Answer:</h3>

761680

<h3>Explanation:</h3>

\sf \boxed{\sum _{n=1}^{44}\:60\left(1.2\right)^{n-2}}

<u>Identify the following's</u>:

First Term [a]  =  60(1.2)ⁿ⁻² = 60(1.2)¹⁻² = 50

Common ratio [r]  =  1.2

Total Terms [n] =  44

===========================

\sf Geometric \ Sum \ of  \ Terms = \dfrac{a(r^n - 1)}{r-1}

===========================

Solving Steps:

<em />\rightarrow \sf \dfrac{a(r^n - 1)}{r-1}<em />

<em />

<em />\rightarrow \sf \dfrac{50(1.2^{44} - 1)}{1.2-1}<em />

<em />

<em />\rightarrow \sf 761679.5808<em />

<em />

\rightarrow \sf 761680 \ \ \  (rounded \ to \ nearest \ integer)

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ΔASA ≅ ΔASA

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