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LuckyWell [14K]
3 years ago
10

When 3x^2-2x+7 is subtracted from 5x^3-4x^2+10 what is the difference

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

If ^ means to divide, then the answer is 2x

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the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
3 years ago
GIVING BRAINLIEST
andriy [413]
D would be the highest value
4 0
3 years ago
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Which of the following describes an angle with a vertex at Z?
Tresset [83]
B is the answer and why is bc I took the quiz
5 0
3 years ago
The graph of
ratelena [41]

Answer:

Positive and negative intervals on a graph

Step-by-step explanation:

The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero). The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero). hope this helps you :)

3 0
3 years ago
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The variable Z is directly proportional to X. When X is 6, has the value of 72. What is the value of Z when X = 13
zalisa [80]
6 / 72 = 13 / z
cross multiply
(6)(z) = (72)(13)
6z = 936
z = 936/6
z = 156 <==
7 0
4 years ago
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