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nikklg [1K]
1 year ago
12

An equilateral is shown inside a square inside a regular pentagon inside a regular hexagon. The square and regular hexagon are s

haded.
An equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon. Write an expression for the area of the shaded regions.

Shaded area = area of the
– area of the + area of the – area of the
Mathematics
2 answers:
Kay [80]1 year ago
8 0

Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle. This can be obtained by finding each shaded area and then adding them.

<h3>Find the expression for the area of the shaded regions:</h3>

From the question we can say that the Hexagon has three shapes inside it,

  • Pentagon
  • Square
  • Triangle

Also it is given that,

An equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon.

From this we know that equilateral triangle is the smallest, then square, then regular pentagon and then a regular hexagon.

A pentagon is shown inside a regular hexagon.

  • Area of first shaded region = Area of the hexagon - Area of pentagon

An equilateral triangle is shown inside a square.

  • Area of second shaded region = Area of the square - Area of equilateral triangle  

The expression for total shaded region would be written as,

Shaded area = Area of first shaded region + Area of second shaded region

Hence,        

⇒ Shaded area  = area of the hexagon – area of the pentagon + area of the  square – area of the equilateral triangle.

 

Learn more about area of a shape here:

brainly.com/question/16501078

#SPJ1

tatiyna1 year ago
8 0

Answer:

Regular Hexagon

Regular Pentagon

Square

Equilateral Triangle

Step-by-step explanation:

E2020 Geometry B!! :3

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Answer:

C) 147 ft²

Step-by-step explanation:

Bottom rectangle:

A = bh

A = 14(7)

A = 98

Top rectangle:

A = bh

A = 7(7)

A = 49

Combined:

98 + 49

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Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
Complementary<br><br>Congruent<br><br>Supplementary<br><br>Similar
Lelu [443]

Answer:

complementary

Step-by-step explanation:


8 0
3 years ago
How do I graph -4x+6y=12
eimsori [14]

You have 2 options.

I will show you the most efficient one, but later I will tell you the other.

-4x+6y=12

6y=4x+12

y=4/6x+12

y=2/3x+12

This tells us the point (0,12) as 12 is where it meets the y-axis (that is why you add it)

And then using the slope, 2/3 we can get (2,15) (which is up 3, right 2)

Just graph those, I would show you exactly, but I cannot add attachments sadly.

The other way (which I won’t show it all as the results would end out with the same line) is to fill in x, then y, with 0

So -4*0+6y=12 which means x=0 and you are solving for y  and -4x+6*0=12 which means y=0 and you are solving for x


8 0
3 years ago
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