It's Dublin - San Juan
Departure Friday at 1:30 Pm (Dublin Time) ==> Time San Juan 9:30 (-4 Hours)
Travel time 16 Hrs ( Dub Sat at 6:30PM) & arriving San JUan on Sat at 9:30 +16;30 26 that means 2 AM (26-24)
Answer:
Step-by-step explanation:
No. Of quarters n(Q)= 3
No. Of dimes n(D) = 5
No. Of nickels n(N) = 2
Total T = 3+5+2 = 10
Prob(D) = n(D)/T = 5/10 = 1/2
Now there are 9 left since it is not replaced back
Prob(Q) = 3/9 = 1/3
Prob(D and Q) = 1/2 × 1/3 = 1/6
Here’s a photo of my working out. There’s heaps of ways to do this but this is what I got...
Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
