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Tomtit [17]
3 years ago
10

GIVING BRAINLIEST

Mathematics
2 answers:
guajiro [1.7K]3 years ago
7 0
Wait what- wouldn’t it be the 2nd one?
andriy [413]3 years ago
4 0
D would be the highest value
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The square root of a negative number, such as StartRoot negative 144 EndRoot, is undefined. Explain why the square root of –x, S
IRINA_888 [86]

Answer:

see the explanation

Step-by-step explanation:

we have

f(x)=\sqrt{-x}

we know that

The radicand of the function cannot be a negative number

so

-x\geq 0

Solve for x

Multiply by -1 both sides

x\leq 0

The domain of the function f(x) is the interval -----> (-∞, 0]

The domain is all real numbers less than or equal to zero

The range of the function f(x) is the interval ----> [0,∞)

The range is all real numbers greater than or equal to zero

<em>Example</em>

For x=144

144\leq 0 ----> is not true

This value of x not satisfy the domain

substitute

f(x)=\sqrt{-144} ----> this value is undefined

For x=-144

-144\leq 0 ----> is true

This value of x satisfy the domain

substitute

f(x)=\sqrt{-(-144)}

f(x)=\sqrt{144}----> this value is defined

therefore

The function will be undefined for all those values of x that do not belong to the interval of the domain of the function

6 0
3 years ago
Read 2 more answers
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poizon [28]

Answer:

3

Step-by-step explanation:

7 0
3 years ago
What is pi x 5 radius squared
Shalnov [3]

Hi!

5^2 is 25

so it's 25pi

or 78.54

Hope this helps!

6 0
3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73
faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

°

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62      [from the standard t table]

Therefore,

CI = (Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})

Thus,

Lower limit of CI =  (Mean - \frac{t\times\sigma}{\sqrt{n}})

or

Lower limit of CI =  (98.3 - \frac{2.62\times0.73}{\sqrt{103}})

or

Lower limit of CI = 98.11

and,

Upper limit of CI =  (Mean + \frac{t\times\sigma}{\sqrt{n}})

or

Upper limit of CI =  (98.3 + \frac{2.62\times0.73}{\sqrt{103}})

or

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and  the mean temperature could very possibly be 98.6°F

7 0
3 years ago
3(x-2)+7=2(x+5)<br> What is the answer to this please
timama [110]

Answer:

x=9

Step-by-step explanation:

distribute: 3x-6+7=2x+10

add like terms: 3x+1=2x+10

add the x's and the integers: x=9

8 0
3 years ago
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