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2 years ago

GIVING BRAINLIEST

Mathematics

2 answers:

guajiro [1.7K]2 years ago

7 0

Wait what- wouldn’t it be the 2nd one?

andriy [413]2 years ago

4 0

D would be the highest value

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If 1m = 3.3 ft, how many cubic feet is the Kuroshio Sea tank? Volume is 9,450. Show your calculations!

Naddika [18.5K]

Answer:

339604.65 cubic feet

Step-by-step explanation:

We are given that 1 m is equal to 3.3 ft.

1 m = 3.3 ft

This means that if we find the volume of a cube of 1 m, we have its volume as:

$1^3 = 1 m^3$

In the same way, the volume of a cube of 3.3 ft (1 m) is:

$3.3^3 = 35.937 ft^3$

This means that:

$1m^3 = 35.937 ft^3$

The Kuroshio sea tank has volume of $9450 m^3$ . Its volume in cubic feet is therefore:

$1m^3 = 35.937 ft^3\\\\9450 m^3 = 9450 * 35.937 = 339604.65 ft^3$

The volume of the tank is 339604.65 cubic feet.

3 0

2 years ago

Which is a prime number a.67 b.65 c.63 d.60

juin [17]

The answer is 67 :)))

4 0

2 years ago

Read 2 more answers

In Triangle XYZ, measure of angle X = 49° , XY = 18°, and

marissa [1.9K]

Answer:

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

$YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X$ (1)

If we know that $X = 49^{\circ}$ , $XY = 18$ and $YZ = 14$ , then we have the following second order polynomial:

$14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}$

$XZ^{2}-23.618\cdot XZ +128 = 0$ (2)

By the Quadratic Formula we have the following result:

$XZ \approx 15.193\,\lor\,XZ \approx 8.424$

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

$XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y$

$\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}$

$Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)$

1) $XZ \approx 15.193$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 54.987^{\circ}$

2) $XZ \approx 8.424$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 27.008^{\circ}$

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

6 0

2 years ago

Triangle ABC is shown below.

Andrew [12]

Answer:

C.) 14

Step-by-step explanation:

Look at the triangle: angles b and c have the same arch, so they are congruent.

In a triangle, if two angles are congruent, then the triangle is isosceles, having two equal sides.

The sides opposite the congruent angles are congruent:

∠B → opposite side → AC

∠C → opposite side → AB

The sides AB and AC are equal. Make an equation:

$AB=AC\\\\2x=3x-7$

Simplify the equation, solving for x. Add 7 to both sides:

$2x+7=3x-7+7\\\\2x+7=3x$

Subtract 2x from both sides:

$2x-2x+7=3x-2x\\\\7=x$

The value of x is 7. Insert the value of x into the given length of AC:

$AC=3(7)-7$

Simplify multiplication:

$AC=21-7$

Subtract:

$AC=14$

Therefore, the length of the line segment AC is 14.

:Done

8 0

2 years ago

A) c< 13 b) c<-) c) c> 13 d) c>-73

Elden [556K]

Answer: what are you trying to ask here?

Step-by-step explanation:

8 0

2 years ago