What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2
x^2 - 2x = 4x + 1
x^2 - 6x - 1 = 0
Yes this is a quadratic
x^3 - 6x^2 + 8 = 0
No this is not a quadratic because the highest power of x is to the power of 3
5x - 3 = 0
No it is not a quadratic because it does not have x^2
2x^2 + 12x = 0
Yes because there's x^2
5x - 1 = 3x + 8
2x - 9 = 0
No because no x^2
9x^2 + 6x - 3 = 0
Yes because there's x^2
A) there is a linear relationship with the test scores go up with increasing hours spent on hw
b) y=8x+40 so at x=3h, y=test score= 8*3+40 = 64
c) 40 represents test score when u spend 0 hour on hw
Your post (" <span>f(x) = 2/3(6)x ") would be clearer and less ambiguous if you'd please format it as follows:
</span><span>f(x) = (2/3)(6)^x. The (2/3) shows that 2/3 is the coefficient of the exponential function 6^x. Please use " ^ " to indicate exponentiation.
Start by graphing </span><span>f(x) = (2/3)(6)^x. The y-intercept, obtained by setting x=0, is (0, 2/3). Can you show that the value of f(x) is (2/3)*6, or 4, at x=1, (2/3)*6^2, or 24, at x = 2, and so on? What happens if x becomes increasingly smaller? The graph approaches, but does not touch, the x-axis.
If you complete this graphing assignment, then all you'd have to do is to flip the whole graph over vertically, reflecting it in the x-axis. You'll see that the graph never touchs the x-axis. Therefore, the range of this flipped graph is (-infinity, 0).</span>
Answer:
x
=
58
5
Step-by-step explanation:
10 times:
→
10
×
The sum of:
→
10
×
(
?
+
?
)
half a number:
→
10
×
(
x
2
+
?
)
and 6:
→
10
×
(
x
2
+
6
)
is 8 :
→
10
×
(
x
2
+
6
)
=
8
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
10
(
x
2
+
6
)
=
8
Multiply out the bracket
5
x
+
60
=
8
Subtract 60 from both sides
5
x
=
58
Divide both sides by 5
x
=
58
5
I believe it's four times as great : )
