Assume that the initial coordinates are (x,y) and that the dilated coordinates are (x',y').
The dilation is therefore:
(x,y) ............> (x',y')
Now, let's assume that the dilation factor is k.
Therefore:
x' = kx
y' = ky
Based on the above, all the student has to do is get the initial coordinates and the final ones and then substitute in any of the above two equations to get the value of k.
Example:
Assume an original point at (2,4) is dilated to coordinates (4,8). Find the dilation factor.
Assume the dilation coefficient is k.
(x,y) are (2,4) and (x',y') are (4,8)
Therefore:
x' = kx .........> 4 = k*2 ..........> k = 2
or:
y' = ky ..........> 8 = k*4 .........> k = 2
Based on the above, the dilation coefficient would be 2.
Hope this helps :)
Answer:
D) SAS
Step-by-step explanation:
Given:
Segment XY = segment VW
Segment XY ║ segment VW
∠ VXY = ∠ WVX (Alternate Interior angle Theorem)
Segment VX ≅ segment VX (relative property of Congruence)
Solution:
In △VWX and △XYV
Segment VX ≅ segment VX
∠ WVX = ∠ VXY
Segment XY = segment VW
∴ By Side Angle Side Congruence Property
△VWX ≅ △XYV by SAS
13=1/6y+2x
-1/6y -1/6y
-1/6y+13=2x
-13 -13
-1/6y=2x-13
*-6 *-6
y=-12x-13
*I multiply it by -6 because -6 is the reciprocal of -1/6, and I can't divide -1/6, actually I can, but it just going to be more confusing that way, and the fastest way to get rid of the -1/6 when you solving this type of equation is multiply it by its reciprocal.
Answer:
2460
Step-by-step explanation:
Hope this helps :)
Itś basically the same thing as a compare and contrast circle graph when they intersect with eachother
