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dem82 [27]
3 years ago
6

Select all of the following that are quadratic equations.

Mathematics
1 answer:
deff fn [24]3 years ago
7 0
What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2

x^2 - 2x = 4x + 1
x^2 - 6x - 1 = 0
Yes this is a quadratic

x^3 - 6x^2 + 8 = 0
No this is not a quadratic because the highest power of x is to the power of 3

5x - 3 = 0
No it is not a quadratic because it does not have x^2

2x^2 + 12x = 0
Yes because there's x^2

5x - 1 = 3x + 8
2x - 9 = 0
No because no x^2

9x^2 + 6x - 3 = 0
Yes because there's x^2
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PLEASE HELP ME i really need help and please show your work
tester [92]
Since the graph is a straight line, we know that this equation follows some sort of y = mx + b format.

Let's take the points that are on the axes (-4,0) and (0,-3)
use them to find the slope = (0 - (-3))/(-4 - 0) = 3/(-4) = -3/4
this is our m in the general equations above
we now have y = (-3/4)x + b
b is the y-intercept which is where x = 0 we already have that point in (0,-3)

plug the -3 in for b to give as a final answer:
y = (-3/4)x - 3
6 0
3 years ago
Kate and Jean paint a house together in 6 days. If they work alone, Kate takes 5 fewer days than Jean would take to do the same
ELEN [110]
Katework+jeanwork=6
work alone
Katework=-5+Jeanwork
ad 5 to both sides
Katework+5=jeanwork
subsitute 5+katework for jeanwork
5+katework+kateworkwork=6
subtract 5 from both sides
2katework=1
divide both sides by 2
katework=0.5days

equation would be
jeanwork+katework=6 and
katework=jeanwork-5 are the equations

5 0
3 years ago
See figure in triangle PQR,ANGLE PQR=90°,segQS seg PR find x,y and z
e-lub [12.9K]

Answer:

x=4√5

y=12

z=6√5

is your answer look it once

3 0
2 years ago
Donnie's height increased by 9 is 74 . Use the variable d to represent Donnie's height.
aliya0001 [1]
D= 74 -9 (which is 65)
5 0
2 years ago
Read 2 more answers
Divide.<br>(3x4 - 3x2 - 6x - 10) = (x - 2)​
alekssr [168]

Answer:

3x^3 + 6x^2 + 15x + 36 + 62 / 3x^4 +3x^2 +6x + 10

Step-by-step explanation:

Use Syenthetic Division

4 0
3 years ago
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