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makvit [3.9K]
3 years ago
15

Coyuntura by five from 135 to 175. Write these Numbers and describe the pattern

Mathematics
1 answer:
Iteru [2.4K]3 years ago
7 0
You are going up by 5
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Simplify the following expression: (1 point)
prohojiy [21]

Answer:

⟼3x {}^{2}  + 12 + y

Step-by-step explanation:

Here,2x − 6y + 3x {}^{2} + 7y − 14x

= 3x {}^{2}  + 2x - 14x - 6y + 7y

= 3x {}^{2}  - 12x - 6y + 7y

= 3x {}^{2}  - 12x + y

6 0
2 years ago
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Help!!! Brainliest to 1 or 2 answer!!
lyudmila [28]

Answer:

35-17=3y

Step-by-step explanation:

3y+17=35

    -17  -17

3y=35-17

7 0
1 year ago
ABC underwent a sequence of rigid transformations to give ABC. Which transformations might have taken place ?
SVEN [57.7K]

Either a reflection across the origin. Or a 180° clockwise rotation.

5 0
3 years ago
I REALLY NEED HELP PLEASE HELP ME :(
o-na [289]

Answer:

I may be wrong but I think 8 is your answer.

Step-by-step explanation:

(-1)^(3/7)  x 128^(3/7)

-1 x 128^3/7

128^(3/7) = 8

= 8

6 0
2 years ago
A skyrocket is launched from a 30–foot-high platform, with initial speed 300 ft/s. If the polynomial −16t2 + 300t + 30 gives the
Stella [2.4K]

Answer:

566 ft

Step-by-step explanation:

Given the polynomial equation

-16t² + 300t + 30 = 0

We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have

-16 * 2² + 300 * 2 + 30

-16 * 4 + 600 + 30

-64 + 630 = 566 ft

Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft

8 0
3 years ago
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