The expressions are irrational 1/3 + √216 and √64+ √353 and the expressions √100 × √100, 13.5 + √81, √9 + √729, and 1/5 + 2.5 are rational number.
<h3>What is a rational number?</h3>
If the value of a numerical expression is terminating then they are the rational number then they are called the rational number and if the value of a numerical expression is non-terminating then they are called an irrational number.
1. √100 × √100
→ √100 × √100
→ 10 × 10 = 100
This is a rational number.
2. 13.5 + √81
→ 13.5 + √81
→ 13.5 + 9 = 22.5
This is a rational number.
3. √9 + √729
→ √9 + √729
→ 3 + 27 = 30
This is a rational number.
4. √64+ √353
→ √64 + √353
→ 8 + √353
This is an irrational number.
5. 1/3 + √216
→ 1/3 + √216
→ 1/3 + √216
This is an irrational number.
6. 1/5 + 2.5
→ 1/5 + 2.5
→ 0.2 + 2.5 = 2.7
This is a rational number.
More about the rational number link is given below.
brainly.com/question/9466779
Answer:
All 1-bedroom apartments in her city only
Step-by-step explanation:
Since the sample of 1-bedroom prices was randomly selected from all complexes in her city, the results can safely be generalized to this population.
Here, DH = HF
x+3 = 3y
x = 3y-3 ----(I)
GH = HE
4x-5 = 2y+3
4x = 2y+8
Substitute value of x,
4(3y-3) = 2y+8
12y-12 = 2y+8
12y-2y = 12+8
10y = 20
y = 2
Now, substitute it in equation 1,
x = 3(2)-3
x = 6-3 = 3
So, your final answer is x=3 & y=2
Let's first find the equation to find what the population went up to. X, will be the population of last year.
1.15x=76,894
Now, we need x by itself, so we need to divide both sides by 1.15.
76,894÷1.15≈66,864
There are decimals, but for this problem, hae .3478 of a person would not fit.
We can check our answer.
66,864×.15=10,029.6
10,029.6+66,864=76,893.6 (rounds up to 76,864)
So the population of the town last year was about 66,864 (66,864.3478) people.
cost of pencil = x = 0.07
and cost of eraser = y = 0.03
Step-by-step explanation:
let cost of pencil = x
and cost of eraser = y
So, we have equations:
![4x+3y=0.37\\3x+4y=0.33](https://tex.z-dn.net/?f=4x%2B3y%3D0.37%5C%5C3x%2B4y%3D0.33)
Solving both equations to find value of x and y
Let:
![4x+3y=0.37\,\,\,eq(1)\\3x+4y=0.33\,\,\,eq(2)](https://tex.z-dn.net/?f=4x%2B3y%3D0.37%5C%2C%5C%2C%5C%2Ceq%281%29%5C%5C3x%2B4y%3D0.33%5C%2C%5C%2C%5C%2Ceq%282%29)
Multiply eq(1) with 4 and eq(2) with 3 and subtract
![16x+12y=1.48\\9x+12y=0.99\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-\\--------\\7x=0.49\\x=0.07](https://tex.z-dn.net/?f=16x%2B12y%3D1.48%5C%5C9x%2B12y%3D0.99%5C%5C-%5C%2C%5C%2C%5C%2C-%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C-%5C%5C--------%5C%5C7x%3D0.49%5C%5Cx%3D0.07)
Putting value of x in equation 1:
![4x+3y=0.37\\4(0.07)+3y=0.37\\0.28+3y=0.37\\3y=0.37-0.28\\3y=0.09\\y=0.03](https://tex.z-dn.net/?f=4x%2B3y%3D0.37%5C%5C4%280.07%29%2B3y%3D0.37%5C%5C0.28%2B3y%3D0.37%5C%5C3y%3D0.37-0.28%5C%5C3y%3D0.09%5C%5Cy%3D0.03)
So, x= 0.07 and y = 0.03
cost of pencil = x = 0.07
and cost of eraser = y = 0.03
Keywords: System of equations
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