Which piecewise defined function is shown on the graph?

Which equation has a graph that goes through the points (4, -6) and (0, 6)?

Ugo [173]

Answer:

$y = -3x + 6\\$

Step-by-step explanation:

Find the gradient of the equation

$\frac{Difference in y}{Difference in x} \\\\\frac{6 - - 6}{0 - 4} = \frac{12}{-4} = -3$

The equation will have the gradient -3x

Use the general equation of a line, and substitute the coordinates in to find the y-intercept.

$y = x + c\\ y = -3x + c\\$

(4, -6)

$-6 = -3(4) + c\\ -6 = -12 + c\\ -6 + 12 = c\\ c = 6$ $6 = -3(0) + c\\ 6 = 0 + c\\ c = 6$

(0, 6)

$6 = -3(0) + c\\ 6 = -0 + c\\ c = 6$

The equation of the line is

$y = -3x + 6\\$

4 0

2 years ago

Sarah has whole milk, which contains 3.25% butterfat by volume, and one type of low-fat milk,

givi [52]

Answer:

D is the answer

Step-by-step explanation:

We want a mixture of low-fat and whole milk to equal 32ounces

Therefore, we know one equation is:

l + w = 32

That 32 ounce mixture should be 2% butter fat

So the amount of butter fat we want is

2% of 32 = 0.64 ounces

At the same time, this mixture contains low-fat and whole milk, which contain 1% and 3.25% butter fat respectively.

therefore, the butter fat in low-fat and whole milk is 0.01l and 0.0325w respectively.

The coefficients are just the percentages in decimal form

Due to the law of conservation of mass,

The addition of these two should yield the final amount of butter fat, meaning the other equation is:

0.01l + 0.0325w = 0.64

7 0

1 year ago

A grade has 81 girls and 72 boys. The grade is spilt into groups that have the same ratio of boys to girls as the whole grade. H

MariettaO [177]

There are 81 girls to every 72 boys in total, which can be represented by 81/72, which put into decimal form, is 1.125. If you then take the number of boys in the group, 16, and multiply it by this number (because the problem states that the ratio is constant) you can find the number of girls in the group.

16*1.125=18

So there are 18 girls in a group with 16 boys.

4 0

2 years ago

Read 2 more answers

The line integral of (2x+9z) ds where the curve is given by the parametric equations x=t, y=t^2, z=t^3 for t between 0 and 1. Pl

Naya [18.7K]

Let r = (t,t^2,t^3)

Then r' = (1, 2t, 3t^2)

General Line integral is:
$\int_a^b f(r) |r'| dt$

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector $\sqrt{(x')^2 + (y')^2 + (z')^2}$

$\int_0^1 (2t+9t^3) \sqrt{1+4t^2 +9t^4} dt$

Fortunately, this simplifies nicely with a 'u' substitution.

Let u = 1+4t^2 +9t^4

du = 8t + 36t^3 dt

$\int_0^1 \frac{2t+9t^3}{8t+36t^3} \sqrt{u} du \\ \\ \int_0^1 \frac{2t+9t^3}{4(2t+9t^3)} \sqrt{u} du \\ \\ \frac{1}{4} \int_0^1 \sqrt{u} du$

After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
$=\frac{1}{4} |_0^1 (\frac{2}{3}) (1+4t^2 +9t^4)^{3/2} \\ \\ =\frac{1}{6} (14^{3/2} - 1)$

7 0

2 years ago

URGENT I NEED HELP RIGHT NOW 5 STAR + BRAINLY

nydimaria [60]

96 is the result 200 x .48

7 0

2 years ago