If they pay $28 for 16 jerseys then the total they’d have to play is $448
28 x 16 = 448
Hope this helps :)
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Answer: $357 is more amount budgeted for food increase.
Explanation:
Since we have given that
Number of people according to the budget = 150
Cost of food per person= $4.25
Total cost of food is given by
If the number of guests attending the opening was 56% more than expected,
So, number of guests now is given by
Total cost of food is given by
Difference between them is given by
Hence, $357 is more amount budgeted for food increase.
1 m = 1 x 10⁶ μm
1 m² = (1 x 10⁶)² μm²
1 m² = 1 x 10¹² μm²
area = 1.5 / 1 x 10¹² m²
Area = 1.5 x 10⁻¹² m²
