Answer: Choice B. sqrt(2)
Draw out a right triangle in quadrant IV as you see in the attached image below. The horizontal and vertical legs are both 1 unit long. To ensure that the signs are properly set up, I am making the vertical leg BC have a label "-1" to mean this is below the x axis. Note how
tan(theta) = opposite/adjacent = BC/AB = -1/1 = -1
Use the pythagorean theorem to find that the hypotenuse AC is sqrt(2) units long
a^2 + b^2 = c^2
(1)^2 + (1)^2 = c^2
2 = c^2
c^2 = 2
c = sqrt(2)
The secant of theta is the ratio of the hypotenuse over the adjacent side, so we end up with
sec(theta) = hypotenuse/adjacent
sec(theta) = AC/AB
sec(theta) = sqrt(2)/1
sec(theta) = sqrt(2) which is why choice B is the answer
The maximum height of the diver would be the y value of the vertex of the graph. The vertex of the graph is (1,4). The maximum height of the diver is 4 meters.
3 1/3 would be the answer
X=60degrees
bc you find 180-125 bc it is a straight angle. You get 55 degrees. Then you add 65+55=120. 180-120=60 degrees. This is because every triangle must have a sum of angles that equals 180 degrees.
Hope this helps.
Answer:
Step-by-step explanation:
You have shared only one graph, that of a quadratic function with vertex at (0, 0) and an equation based upon y = ax^2, where a is a constant coefficient.
Please go back to the source of your question and describe the other graphs that were given to you.
The graph that shows a straight line is the linear function.
