No entiendo nada por favor explícame
Answer:
Step-by-step explanation:
Let the 3 numbers be 4x , 5x and 6x
4x + 6x = 5x + 55
10x = 5x + 55 Subtract 5x from both sides.
<u> 5x 5x</u>
5x = 55 Divide by 5
x = 55/5
x = 11
Therefore the numbers are
3*11 = 33
4*11 = 44
5*11 = 55
The answer rewritten is z^2/25
A)
The discriminant (radicand) is √(b^2-4ac), let us call this "d" for the discriminant.
If:
d<0, there are no real solutions (though there are two imaginary ones)
d=0, there is one real solution
d>0, there are two real solutions.
In this case, d=12^2-4(4)9
d=144-144
d=0
So there is one real solution.
B)
9x^2-30x+25=0
9x^2-15x-15x+25=0
3x(3x-5)-5(3x-5)=0
(3x-5)(3x-5)=0
(3x-5)^2=0
x=5/3
x=1 2/3
Answer:
Step-by-step explanation:
If the smallest number is 'x', then the other number = x +1
x*(x+1)= 420
Use distributive property
x*x + x*1 = 420
x² + x - 420 =0 ------> this is the required quadratic equation.
