Answer:
C
Step-by-step explanation:
If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18,
x=(m+9)/2
y=(2m+15)/2
z=(3m+18)/2
the average of x, y, and z
=(x+y+z)/3
=(m+9+2m+15+3m+18)/3
=(6m+42)/3
=2m+14
ans is C
A. It passes the vertical line test
Answer:
<u>2/5 < 5/8 < 6/7 < 1 </u>
<u>OR</u>
<u>1 > 6/7 > 5/8 > 2/5</u>
Step-by-step explanation:
It is required to compare Two-fifths, Six-sevenths, Five-eighths, and 1
Two-fifths = 2/5
Six-sevenths = 6/7
Five-eighths = 5/8
So, the given numbers are: 2/5, 6/7, 5/8, and 1
We need to make the numbers in order from the least to the greatest or from the greatest to the least
The easy method is convert the rational numbers to decimal numbers
So,
2/5 = 0.4
6/7 ≈ 0.857
5/8 = 0.625
1 = 1
So, the numbers form the least to the greatest are:
0.4 , 0.625 , 0.857 , 1
So,
2/5 , 5/8 , 6/7 , 1
The inequality correctly compares the numbers are:
<u>2/5 < 5/8 < 6/7 < 1</u>
Or can be written from the greatest to the least as:
<u>1 > 6/7 > 5/8 > 2/5 </u>
I think it is 432.sorry if it is wrong though. My bad calculation error.