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Simora [160]
3 years ago
15

which of the following describes the placebo effect? A. Subjects are prevented from knowing whether they are receiving real drug

s or placebos. B. At least one block of subjects in a experiment receives only placebos. C. Subjects may respond to a treatment simply because they believe it is affecting them. D. Subjects receive inactive sugar pills instead of real medication. E. An experiment is repeated many times with real drugs and placebos.
Mathematics
2 answers:
Lady_Fox [76]3 years ago
6 0

The answer would be (C) Subjectsmay respond to a treatment simply because they believe it is affecting them

Lelu [443]3 years ago
4 0

Correct answer choice is:

C. Subjects may respond to a treatment simply because they believe it is affecting them.

Explanation:

A placebo is a material or procedure of no predetermined therapeutic utility. General placebos comprise inactive tablets, inactive injections, false surgery, and other methods.

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Find the general indefinite integral. (use c for the constant of integration. )
Vlada [557]

The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0
2 years ago
How to simplify 4/10 what's the answer?
Pani-rosa [81]
4/10 is 2/5 or 0.4 in decimal form.
3 0
3 years ago
Find the area of a regular octagon with an apothem of 8
xenn [34]

Answer:

308cm²

Step-by-step explanation:

Assuming the given unit is in cm

The expression for the area of a regular Octagon is

A=2(1+√2)a²

Given the apothem a = 8cm

Substituting we have

A=2(1+√2)8²

A= 2(1+1.414)64

A= 2(2.414)64

A= 308cm²

6 0
3 years ago
Help me please with this math question! giving brainliest to the correct answer
Gwar [14]

Step-by-step explanation:

do 21×3.14= 65.94

then divide by 2 since its a semicircle

equals: 32.97

than find perimeter altogether

21+28+28+32.97= 109.97ft

5 0
3 years ago
Read 2 more answers
Simplify this expression.
nexus9112 [7]

Answer:

C

Step-by-step explanation:

If you would recall one of the laws of exponents, when dividing powers of the same base you subtract their exponents. So for this expression:

6⁷ ÷ 6⁵ = 6^(7-5) = 6² =36

4 0
2 years ago
Read 2 more answers
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