I’m assuming 3/4x is a fraction
the coordinates are (0,-4) and (4,-1)
Angle TQS is equal to 74 degrees
Find the value of -6(-2)^2 - 4^2 - 3(-2x^4).
-6(-2)^2 - 4^2 - 3(-2x^4)
Multiply -6(-2)^2.
12^2 - 4^2 - 3(-2x^4)
Subtract 12^2 and -4^2.
8 - 3(-2x^4)
Distribute -3(-2x^4).
8 + 6x^4
Therefore the value of 6(-2)^2 - 4^2 - 3(-2x^4) is 8 + 6x^4.
We use the pithagorean formula: x^2 = 130^2 - 50^2 = 16900 -2500 = 14400;
then, x =
= 120 feet has the other dimension of the lot.
Formula for the area of a quarter circle: A = (pi x r^2) / 4
A = (pi x 1^2) / 4
A = 1pi / 4
A = 0.79 square centimeters
Hope this helps! :)
