According to the direct inspection, we conclude that the best approximation of the two solutions to the system of <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)
<h3>What is the solution of a nonlinear system formed by two quadratic equations?</h3>
Herein we have two parabolae, that is, polynomials of the form a · x² + b · x + c, that pass through each other twice according to the image attached to this question. We need to estimate the location of the points by visual inspection on the <em>Cartesian</em> plane.
According to the direct inspection, we conclude that the best approximation of the two solutions, that is, the point where the two parabolae intercepts each other, to the system of two <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)
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12x + (-3y) + 4x + (-z)
12 (3) + -3 (13) + 4 (3 ) + (-5)
36 + -39 + 12 + (-5)
36 + 12 -39 - 5
48 - 44
4
Okay well the way I do it is like this. When ever the next hour hits 10 minutes that is one hour then add the minutes left. So from 7:10a.m. to 6:10p.m. is 11 hours. Now the rest of the minutes. 6:35 -6:10=:25. So she has been away from the house for 11 hours and 25 minutes
Answer:
20 mph
Step-by-step explanation:
First problem:
The new speed is 26 mph.
The old speed was x.
The new speed is 30% higher than the old speed.
1.3x = 26
x = 20
Answer: 20 mph
Second problem:
A number, perhaps a percent or a fraction, is missing from the problem.
Answer:
See below
Step-by-step explanation:
Its an equation of decay because continuous multiplication by 0.98 decreases the value of the function as x increases. Its gradual slow decay because 0.98 is just below 1. The graph will pass through the point (0,230) ( when x = 0) and is continuous over the range of all real numbers. The graph is not a straight line but slightly curved.