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2 years ago

Please help me find x

Mathematics

1 answer:

Luda [366]2 years ago

8 0

Answer is 3x because u do 12-9 which gets three and since it was originally 12x and you don’t know what X is you just put the x on the 3 and get 3x

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Problem How many numbers between 111 and 100100100 (inclusive) are divisible by 101010 or 777?

olga2289 [7]

I suspect you meant

"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"

• Count the multiples of 10:

⌊100/10⌋ = ⌊10⌋ = 10

• Count the multiples of 7:

⌊100/7⌋ ≈ ⌊14.2857⌋ = 14

• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and

⌊100/70⌋ ≈ ⌊1.42857⌋ = 1

(where ⌊x⌋ denotes the "floor" of x, meaning the largest integer that is smaller than x)

Then using the inclusion/exclusion principle, there are

10 + 14 - 1 = 23

numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.

6 0

3 years ago

Graph the line passing through the given point and having the given slope (0,3), m=4

andriy [413]

Hint :-

To find out the equation of the line we can use the point slope form of the line which is $y - y_1 = m(x-x_1)$

Solution :-

The given point to us is , $(0,3)$ and the slope of the line is 4 . On using the point slope form , we have ,

$\implies y - y_1= m(x-x_1) \\\\\implies y-3 = 4(x-0) \\\\\implies y -3 = 4x \\\\\implies \boxed{ 4x - y + 3 =0}$

Hence the equation is 4x - y + 3 = 0 

( for graph , see attachment ) .

3 0

2 years ago

I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know

azamat

By definition of conditional probability,

$P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}$

$=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}$

Assuming a standard 6-sided fair die,

if $X_1=4$ , then $X_1+X_2=7$ means $X_2=3$ ; otherwise,
if $X_2=4$ , then $X_1=3$ .

Both outcomes are mutually exclusive with probability $\frac1{36}$ each, hence total probability $\frac2{36}=\frac1{18}$ .

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

and so a sum of 7 occurs $\frac6{36}=\frac16$ of the time.

Then the probability we want is

$P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13$

6 0

3 years ago

Help me pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Slav-nsk [51]

Answer:

A, 2 5/8 cups

Step-by-step explanation:

Since six dozen brownies is three times as much as two dozen, we can multiply 7/8 cups by 3. 3 x 7/8 = 21/8 If we simplify this fraction, it is 2 5/8. Therefore the answer is A, 2 5/8 cups.

4 0

3 years ago

Read 2 more answers

I need help with this!!! Which has a greater area, a triangle with a base of 100 feet and a height of 100 feet or a circle with

nevsk [136]

I believe it is a Triangle with a base of 100 ft. and a height of 100 ft.
Yet that's what I learned in class, my teacher isn't paying attention to much of our lessons, so forgive me if this is wrong.

5 0

3 years ago