How many different ways can 9 books be arranged on a bookshelf?

Mathematics

1 answer:

Darina [25.2K]4 years ago

5 0

We use the fundamental counting principal.

This states that there are 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 ways

for nine books to be arranged on a bookshelf.

The answer is attached below.

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The perimeter of quadrilateral JKLM is 90 centimeters. Which is the length of side KL?

fenix001 [56]

The perimeter of an object is given by the sum of all the sides of the object. Thus the perimeter of a quadrilateral is the sum of the four sides of the quadrilateral.

Given a quadrilateral with sides: n, 2n - 12, 3n + 4, n + 7

The sum is n + 2n - 12 + 3n + 4 + n + 7 = 7n - 1 = 90

Thus, 7n = 90 + 1 = 91 and n = 91 / 7 = 13.

Therefore, the length of the side KL is n = 13 centimeters.

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Answer:

Step-by-step explanation:

-3x + 4y = 12

12(1/4x - 1/3y = 1)

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2 years ago

A card is drawn randomly from a standard 52-card deck. Find the probability of the given event. (a) The card drawn is 5. The pro

Dmitrij [34]

Answer:

a. 1 / 13
b. 3 / 13
c. 10 / 13

Step-by-step explanation:

There are four 5's in the deck. This means that, from 52 possible cards to drawn, we have 4 chances of drawing a 5. This means that the probability will be:

$p = \frac{4}{52}$

$p = \frac{1}{13}$

For every suit, there are three face cards, J, Q and K. There are 4 suits, so, the total number of face cards its:

$4 * 3 = 12$

The total possible cards are, still, 52, so, the probability will be

$p = \frac{12}{52}$

$p = \frac{3}{13}$

We know that the card drawn must be a face card, o not being a face card. There is no third choice here. So, the probability of drawing a face card OR not drawing a face car its:

$p = \frac{52}{52} = 1$