Question

5x + 2y = 12 5x – 2y = 28 Solve by substitution

Answer 1

Answer:

Divide each term by  

5

and simplify.

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x

=

2

y

5

+

12

5

4

x

=

28

−

3

y

Replace all occurrences of  

x

in  

4

x

=

28

−

3

y

with  

2

y

5

+

12

5

.

x

=

2

y

5

+

12

5

4

(

2

y

5

+

12

5

)

=

28

−

3

y

Simplify  

4

(

2

y

5

+

12

5

)

.

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x

=

2

y

5

+

12

5

8

y

5

+

48

5

=

28

−

3

y

Move all terms in  

8

y

5

+

48

5

=

28

−

3

y

to the left side and simplify.

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x

=

2

y

5

+

12

5

23

(

y

−

4

)

5

=

0

Solve for  

y

in the second equation.

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x

=

2

y

5

+

12

5

y

=

4

Replace all occurrences of  

y

in  

x

=

2

y

5

+

12

5

with  

4

.

x

=

2

(

4

)

5

+

12

5

y

=

4

Simplify  

2

(

4

)

5

+

12

5

.

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x

=

4

y

=

4

The solution to the system of equations can be represented as a point.

(

4

,

4

)

The result can be shown in multiple forms.

Point Form:

(

4

,

4

)

Equation Form:

x

=

4

,

y

=

4

Step-by-step explanation: