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wolverine [178]
3 years ago
10

Maths question help plz

Mathematics
1 answer:
Burka [1]3 years ago
5 0
{4.4}^{2} + {4.4}^{2} = {x}^{2}
and you will end up with the solution 6.22 centimeters
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Solve the system using elimination.<br> A. (2, 1)<br> B. (0, –2)<br> C. (–2, 0)<br> D. (1, 2)
stich3 [128]

Answer:b

Step-by-step explanation:

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Harriest makes yo-yos. she needs 38 inches of string for each yo-yo. How many yo-yos can she make with 875 inches of string? How
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What is the equation of the graph? y = 4x y = x y = -x y = -4x
Vinil7 [7]

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3 years ago
A random sample of 100 teletype operators indicates that their salaries fluctuate quite a bit. The sample Standard deviation of
ELEN [110]

Answer:

\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}

80.341 \leq \sigma^2 \leq 128.495

Now we just take square root on both sides of the interval and we got:

8.963 \leq \sigma \leq 11.336

Step-by-step explanation:

Data given and notation

s=10 represent the sample standard deviation

\bar x represent the sample mean

n=100 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=100-1=99

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,99)" "=CHISQ.INV(0.95,99)". so for this case the critical values are:

\chi^2_{\alpha/2}=123.225

\chi^2_{1- \alpha/2}=77.046

And replacing into the formula for the interval we got:

\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}

80.341 \leq \sigma^2 \leq 128.495

Now we just take square root on both sides of the interval and we got:

8.963 \leq \sigma \leq 11.336

5 0
3 years ago
4/10 divided by 5/8. please answer
stiv31 [10]

Answer:

16/25

Step-by-step explanation:

got it on calculator

4 0
4 years ago
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