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3 years ago

Maths question help plz

Mathematics

1 answer:

Burka [1]3 years ago

5 0

${4.4}^{2} + {4.4}^{2} = {x}^{2}$
and you will end up with the solution 6.22 centimeters

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36 моля колкото по бързо може формулата е (X÷2)÷(x×3)=305,4

bazaltina [42]

Answer:

Step-by-step explanation:

The quotient of two numbers is 305.4. Find the quotient if the divisor decreases 2 times and the divisor increases 3 times

x/y = 305.4

3x/(y/2) = 6x/y = 6*305.4 = 1832.4

Note that the question will be deleted soon because it is posted in a language other than English.

Обратите внимание, что вопрос будет удален в ближайшее время, потому что он размещен на языке, отличном от английского.

6 0

3 years ago

Three different sets of objects contain 4, 5, and 12 objects, respectively. How

Angelina_Jolie [31]

Answer:

$\text{B. }240}$

Step-by-step explanation:

$\binom{4}{1}\cdot\binom{5}{1}\cdot \binom{12}{1}=\boxed{\text{B. }240}}$

(Multiplying each of the numbers also yields 240)

4 0

3 years ago

Suppose that 15 inches of wire costs 45 cents. At the same rate, how many inches of wire can be bought for 24 cents? Please help

Tanya [424]

$15\ inches\ cost\ 45\ cents\\
x\ inches\ cost\ 24\ cents\\\\
proportion:\\
15-45\\
x-24\\\\
cross\ multiplication\\\\
15*24=45x\\\\
360=45x\ \ \ | divide\ by\ 45\\\\
x=8\\\\
8\ inches\ of \ wire\ cost\ 24\ cents.$

6 0

3 years ago

Free Points!!....what is the best restaurant

Rainbow [258]

Answer:

ummmmm panda express ig

Step-by-step explanation:

im just in the mood for chinese food rn lol

5 0

4 years ago

Read 2 more answers

Suppose the number of hits a webpage receives follows a Poisson distribution. The average number of hits per minute is 2.4. What

REY [17]

Answer:

The probability that the page will get at least one hit during any given minute is 0.9093.

Step-by-step explanation:

Let X = number of hits a web page receives per minute.

The random variable X follows a Poisson distribution with parameter,

λ = 2.4.

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

Compute the probability that the page will get at least one hit during any given minute as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-\frac{e^{-2.4}(2.4)^{0}}{0!}\\=1-\frac{0.09072\times1}{1} \\=1-0.09072\\=0.90928\\\approx0.9093$

Thus, the probability that the page will get at least one hit during any given minute is 0.9093.

6 0

3 years ago