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2 years ago

What is the period of the function F(x) = -4 sec(1/2x)?

Mathematics

1 answer:

k0ka [10]2 years ago

3 0

4π is the pe riod of the function F(x) = -4 sec(1/2x).

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garik1379 [7]

Answer:

Step-by-step explanation:

Hope this helps!

4 0

3 years ago

Read 2 more answers

Evaluate 2 tan 45 - tan 60

Darya [45]

Answer:

2 - √3

Step-by-step explanation:

tan45 = 1

tan60 = √3

2 tan 45 - tan 60

2(1) - √3

=> 2 - √3

6 0

3 years ago

Read 2 more answers

a rhombus as an area of 72 ft and the product of the diagonals is 144. What is the length of each diagonal?

SashulF [63]

A = (1/2)(x)(y)

Let x = diagonal 1

Let y = diagonal 2

The product of xy = 144.

This means that x = 12 and y = 12.

So, 12 • 12 = 144

Each diagonal is 12 feet.

Prove:

72 feet = (1/2)(12)(12) feet

72 feet = (1/2)(144) feet

72 feet = 72 feet

6 0

3 years ago

Use the model to solve the equation 3/8 +2/8

torisob [31]

3+2=5
5/8. Hope that helps!

6 0

3 years ago

A researcher takes a simple random sample of 83 homes in a city and finds that the mean square footage is 1628 with a standard d

Anna [14]

Answer: (1583.63, 1672.37)

Step-by-step explanation:

Given : Sample size : n= 83

Sample mean : $\overline{x}=1628$

Sample standard deviation : $\sigma=243$

The population standard deviation $(\sigma)$ is unknown .

The confidence interval for population mean :

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}$

For 90% confidence , significance level = $\alpha=1-0.90=0.10$

Using t-distribution table , Critical t-value = $t_{(\alpha/2, n-1)}=t_{0.05,82}=1.6636$

, where n-1 is the degree of freedom.

Now , 90% confidence interval for the mean square footage of all the homes in that city will be :-

$1628\pm (1.6636)\dfrac{243}{\sqrt{83}}\\\\ 1628\pm (1.6636)(26.672715)\\\\\\\\\approx1628\pm 44.37\\\\=(1628- 44.37,\ 1628+ 44.37)\\\\=(1583.63,\ 1672.37)$

Hence, the 90% confidence interval for the mean square footage of all the homes in that city = (1583.63, 1672.37)

7 0

3 years ago