Sin(2θ)+sin(<span>θ)=0
use double angle formula: sin(2</span>θ)=2sin(θ)cos(<span>θ).
=>
2sin(</span>θ)cos(θ)+sin(<span>θ)=0
factor out sin(</span><span>θ)
sin(</span>θ)(2cos(<span>θ)+1)=0
by the zero product property,
sin(</span>θ)=0 ...........(a) or
(2cos(<span>θ)+1)=0.....(b)
Solution to (a): </span>θ=k(π<span>)
solution to (b): </span>θ=(2k+1)(π)+/-(π<span>)/3
for k=integer
For [0,2</span>π<span>), this translates to:
{0, 2</span>π/3,π,4π/3}
たはたらさあらたはたはあらたさらやたはまさらたはまりあはらたはたさたはあらあらたはたひたはらたら、らま、らま、らまはたはたはさまらたらまはあはあらたはたひまひはたらたはまはたらまはた
Answer:
-1
Step-by-step explanation:
Has to be the opposite
