Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
Answer:
y=4x+7
Step-by-step explanation:
You can find the slope of the line by using the formula of change and y over change in x. ∆y/∆x OR (y2-y1)/(x2-x1)
11-3=8
1--1=2
8/2=4
Let's plug in a y value 3.
3=4*-1+b
b=7
Once you found b rewrite your equation in slope intercept form.
y=4x+7
You can check this equation by plugging in the unused coordinate (1,11) and find it balances.
In 1)
Line 1 has following coordinates.
(0,0) ; (1,-2) ; (2,-4)
Line 2 has following coordinates.
(0,0) ; (1,0.5) ; (2,1)
Line 3 has following coordinates.
(0,1) ; (1,1.5) ; (2,2)
If you'll draw the lines, you'll observe that Line 1 is perpendicular to Line 2 and Line 3 and Line 2 and Line 3 are parallel to each other.
So,
Option D will be correct.
The answer is B The function shown on the graph has a smaller rate of change but a higher starting point