<h3>
Answer: -i</h3>
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Explanation:
i = sqrt(-1)
Lets list out the first few powers of i
- i^0 = 1
- i^1 = i
- i^2 = -1
- i^3 = i*i^2 = i*(-1) = -i
- i^4 = (i^2)^2 = (-1)^2 = 1
By the time we reach the fourth power, we repeat the cycle over again (since i^0 is also equal to 1). The cycle is of length 4, which means we'll divide the exponent over 4 to find the remainder. Ignore the quotient. That remainder will determine if we go for i^0, i^1, i^2 or i^3.
For example, i^5 = i^1 because 5/4 leads to a remainder 1.
Another example: i^6 = i^2 since 6/4 = 1 remainder 2
Again, we only care about the remainder to find out which bin we land on.
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Turning to the question your teacher gave you, we have,
739/4 = 184 remainder 3
So i^739 = i^3 = -i
<h3>
-i is the final answer</h3>
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Side notes:
- if i^a = i^b, then a-b is a multiple of 4
- Recall that the divisibility by 4 trick involves looking at the last two digits of the number. So i^739 is identical to i^39.
Answer:
1. algebraic expression: a mathematical expression containing one or more variables
2. coefficient: the constant preceding the variables in a product
3. constant: a numerical value
4. expression: a mathematical phrase that cannot be determined true or false
5. variable: a letter or symbol used to represent an unknown
Step-by-step explanation:
The answer is 35 because that's not a multiple of 8
Answer:
Step-by-step explanation:
I can not answer because the information is not specific and not enough to be answered
first off, I'd like to point out that for the 5th test, he has 96, and that's +6 above 90, and therefore it should be 6.
if all the above/below numbers, summed up yield 0, that simply means the average is an even 90 on average for all 6 tests, if they yield above 0, is above on the average, and if it's below 0, a negative value, he needs to do more work.
-7+4-11+7+6-3 = -4.
you can think of it this way, if he had 90 on all 6 tests, the above/below row will show 0, 0, 0, 0, 0, 0. If any of the tests was above 90, that row will yield a sum more than 0, and if any of the tests were below, that sum will be a negative value.
