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AnnyKZ [126]
3 years ago
13

HELP ASAP PLEASE!!!!!!!!!!!!!!!

Mathematics
1 answer:
TiliK225 [7]3 years ago
8 0
ITS D!! It’s the third option !!
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What is the slope of this line?​
Fed [463]

Answer:

(-5,4)

Step-by-step explanation:

My answer is probably incorrect .-. ._. but I tried my best :) and this is what I got

Hope This Helps

7 0
3 years ago
Read 2 more answers
Help please, and explain(step-by-step) how the answer would be correct.
vekshin1

When a function is reflected, it must be reflected over a line

The new function is: y = |4 -x| -8

The equation is given as:

y = |x + 4| - 8

The rule of reflection over the y-axis is:

(x,y) \to (-x,y)

So, we have:

y = |-x + 4| -8

Rewrite as:

y = |4 -x| -8

Hence, the new function is:

y = |4 -x| -8

Read more about reflections at:

brainly.com/question/938117

8 0
2 years ago
Someone please help me I have to show how they're similar
Sidana [21]
Angle AXD = angle CXB (vertically opposite angle)
then angle ADB = angle ABC 
then angle DAB = angle BCD 
I couldn't remember the name of the rule 
I said that they are equal if you look at the curve AC and DB
They called them that two angles that subtended by the same mirror (arc)
lead them to be a similar angle (angle - angle - angle)
3 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
What’s the property of a + 0 = a
jek_recluse [69]

Answer:Identity property

Step-by-step explanation:

6 0
3 years ago
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