Answer:
The system has one solution.
Step-by-step explanation:
To find the number of solutions of the system, we equal both equations for y.
If we have ax = b, in which both a and b are different of 0, we have one solution.
If both a and b are 0, we have infinite solutions.
If a is 0 and b is not, there are no solutions.
y=6/7x-8 and y=7/9x+10/9
So





Both a and b are different of 0, so the system has one solution.
Answer:
Domain: {-2, -3, 6, 8, 10}
Range: {-5, 1, 7, 9}
Step-by-step explanation:
Given:
{(6, -5), (-2, 9), (-3, 1), (10, 7), (8, 9)}
✔️Domain:
This includes all the set of the x-values that are in the relation. This includes, 6, -2, -3, 10, and 8.
Thus, the domain can be represented as:
{-2, -3, 6, 8, 10}
✔️Range:
This includes all corresponding y-values in the relation. They are, -5, 1, 7, and 9.
Range can be represented as:
{-5, 1, 7, 9}
Answer:
x=
- 
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Mean of four numbers a, b, c, and d is 8:</u>
- (a + b + c + d)/4 = 8
- ⇒ a + b + c + d = 32
<u>Mean of seven numbers x, y, z, a, b, c and d is 12:</u>
- (x + y + z + a + b + c + d)/7 = 12
<u>Substitute the sum of 4 numbers:</u>
- x + y + z + 32 = 7*12
- x + y + z = 84 - 32
- x + y + z = 52
<u>Mean of x, y and z is:</u>
Answer:
76.16 kilograms of food
Step-by-step explanation:
Number of cyclist = 32
Food per cyclist = 8.33 kilograms
Days of the trip = 7 days
Food per cyclist per day = 8.33 kg / 7
= 1.19kg food per day for each cyclist
how many kilograms of food will the group be carrying at the end of Day 5?
5 days out of 7 days = 2 days
Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days
= 2 × 1.19
= 2.38 kilograms of food for two days
32 cyclist for 2 days = 32 × 2.38 kg of food
= 76.16 kilograms of food
The group will be carrying 76.16 kilograms of food at the end of Day 5