Since you're painting the sides of the cube, you will need the equation for the surface area of a cube, which is
![SA = 6s^{2}](https://tex.z-dn.net/?f=SA%20%3D%206s%5E%7B2%7D%20)
, where SA = surface area and s = length of an edge of the cube.
You're told that the edge length, s = 2cm. Plug this into the equation for surface area:
The surface area that will be painted is <span>
24 cm².</span>
AAS Postulate
It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.
Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate.
Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!
M=64
Add 6 to both sides to get m=64
4) Here both smaller and larger triangle is "isosceles" in nature.
So, sum would be 180 with two equal sides.
66 + BDE + BED = 180
2 BDE = 180 - 66
BDE = 114 / 2
BDE = 57
<span>In short, Every four angles would be equal to 57
</span>5) A) 7
It is because it must be smaller than the longest side which is equal to 8
6) D) Yes, Because ∠C is congruent to ∠BED
Hope this helps!