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Alex787 [66]
3 years ago
8

Help me pls i am going to fail if i get this question wrong

Mathematics
1 answer:
never [62]3 years ago
8 0

Answer:

you should fail :)

Step-by-step explanation:

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A bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty. Find the
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Answer:

Therefore, the probability is P=1/84.

Step-by-step explanation:

We have a  bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty.

We conclude that in a bag have 9 tokens.  

We calculate the probability that the red tokens are drawn consecutively.

We calculate the number of possible combinations:

C_3^9=\frac{9!}{3!(9-3)!}=84\\\\

Number of favorable combinations is 1.

Therefore, the probability is P=1/84.

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Step-by-step explanation:

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Your friend earns $10.50 per hour. This is 125% of her hourly wage last year. How much did your friend earn per hour last year?
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You flip a coin and then roll a 6-sided number cube (a die).
expeople1 [14]

Answer:

a)  No, it does not matter whether you roll the die or flip the coin first, as these two events are <u>independent</u> of each other, which means they do not affect each other.

b) Yes.

  • Let event 1 be flipping a coin and event 2 be rolling a die.
  • Let event 1 be rolling a die and event 2 be flipping a coin.

The likelihood that any outcome will occur will not change, as the events are independent.

c) see attached

d)   12 outcomes  (H = head, T = tail, numbers represent the value of the die)

H 1           T 1

H 2          T 2

H 3          T 3

H 4          T 4

H 5          T 5

H 6          T 6

e)  

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

\implies \sf P(even)=\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}

\implies \sf P(head)=\dfrac{1}{2}

\implies \sf P(even)\:and\:P(head)=\dfrac{1}{2} \times \dfrac{1}{2}=\dfrac{1}{4}

6 0
2 years ago
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