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exis [7]
3 years ago
15

4+4+4+4what is 4 + 4 + 4 + 4 ​

Mathematics
2 answers:
vredina [299]3 years ago
8 0

Answer 16

Step-by-step explanation:

4+4=8+4=12+4=16

OR

4×4=16

Liula [17]3 years ago
3 0

Answer:

16

Step-by-step explanation:

4

4 + 4 = 8

8 + 4 = 12

12 + 4 = 16

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F (x) = 4x + 7. Find the inverse of f(x).
Brilliant_brown [7]

Answer:

C. f(x) = x - 7 all over 4

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NB: Let f(x) = y

Exchange X and Y

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6 0
3 years ago
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
3 years ago
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