The denominator( s ) we are given are
, and . The first thing we want to do is factor the expressions, to make this easier -

This expression is a perfect square, as ( x )^2 = x^2, ( 2 )^2 = 4, 2 * ( x ) * ( 2 ) = 4x. Thus, the simplified expression should be the following -

The other expression is, on the other hand, not a perfect square so we must break this expression into groups and attempt factorization -

Combining ( x + 2 )^2 and ( x + 2 )( x + 3 ), the expression that contains factors of each is ( x + 2 )^2 * ( x + 3 ), or in other words the LCM.
<u><em>Solution = </em></u>
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