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4 years ago

11

Are the two triangles below similar ?

2 answers:

Strike441 [17]4 years ago

6 0

Answer:

No because the bottom one is an acute triangle but the top one is obtuse.

Hope this helped! :3

forsale [732]4 years ago

6 0

Answer:

Hi there!

The answer to this question is: yes they're indeed similar

Step-by-step explanation:

As you can see both triangle have 30 degrees on the bottom corner of the triangle.

Then if you look at triangle ABC, they give you angle ACB which is 65 degrees. Using the triangle sum theorem you can figure out the measure of the last angle is 85. This angle corresponds with angle FED on the smaller triangle. Then if you look at both side AC and side FD they are half each others length therefore they are similar

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(-1,3) (3,0) (-1.-2) find perimiter

KATRIN_1 [288]

Answer:

$p$ ≈ $14.5$

Step-by-step explanation:

Find the distance between the three pairs first using the distance formula:

$\sqrt{(x2-x1)^2+(y2-y1)^2}$

Take the first two points, $(-1,3)(3,0)$ and insert the values:

$\sqrt{(3-(-1))^2+(0-3)^2}$

Simplify parentheses (two negatives makes a positive):

$\sqrt{(3+1)^2+(0-3)^2}\\\\ \sqrt{(4)^2+(-3)^2}\\\\\sqrt{16+9}\\ \\\sqrt{25}=5$

The distance between the first two points is 5. Use the nest two points, $(3,0)(-1,-2)$ and insert values:

$\sqrt{(-1-3)^2+(-2-0)^2}$

Simplify parentheses:

$\sqrt{(-4)^2+(-2)^2}\\ \\\sqrt{16+4} \\\\\sqrt{20}=4.5$

The distance between the nest two point is about 4.5. Use the remaining two points, $(-1,-2)(-1,3)$ and insert values:

$\sqrt{(-1-(-1))^2+(3-(-2))^2}$

Simplify parentheses (two negatives makes a positive):

$\sqrt{(-1+1)^2+(3+2)^2}\\\\\sqrt{(0)^2+(5)^2}\\ \\\sqrt{0+25}\\ \\\sqrt{25}=5$

The distance between the last points is 5. Add the distances together to find the perimeter of the triangle:

$5+4.5+5\\10+4.5\\14.5$

The perimeter is about 14.5.

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3 years ago