<h2>area of shaded portion = 49.5 yd²</h2><h2>____________________</h2>
<u>Step-by-step explanation:</u>
radius of circle = 5 yd ------ ( <em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em> </em><em>)</em>
height of triangle = 16 yd --- ( <em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em> </em><em>)</em>
base of triangle = 16 yd ----- ( <em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em> </em><em>)</em>
area of triangle = 1/2 × base × height
= 1/2 × 16 × 16
= 128 yd²
area of circle = π × radius²
= 3.14 × 5 × 5 --- ( π = 3.14 )
= 78.5 yd²
<h2>---------------------------------------</h2>
area of shaded portion = area of triangle - area of circle
area of shaded portion= 128 yd²-78.5 yd²
area of shaded portion = 49.5 yd²
<h2>--------------------------------------</h2><h2>PLEASE FOLLOW ME</h2>
Answer:
(B)The GCF of the numbers(28 and 36) in each term in the expression is 4.
(C)The GCF of the variables(a and ab) in each term in the expression is a.
(E)The factored form of the expression is 4a(7+9b)
Step-by-step explanation:
Given the expression: 
If we write it as a product, we obtain:
We can see the following
- The GCF of the numbers(28 and 36) in each term in the expression is 4.
- The GCF of the variables(a and ab) in each term in the expression is a.
- The factored form of the expression is 4a(7+9b)
The correct options are B, C, and E.
Answer:
No
Explanation:
Cube A surface area is : 2x2x6 (because there are 6 faces) = 24
Cube B surface area is 4x4x6 = 96
The surface area of the cube B isn't the twice of cube A's surface area
Now the volumes :
Cube A volume is 2x2x2 = 8
Cube B volume is 4x4x4= 64
Cube B's volume isn't the twice of cube A's volume
Domain: The set of all real numbers
We can plug in any x value we want and there aren't any restrictions. There aren't any holes, jumps, gaps, or asymptotes
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Range: Only one value is in the range and it is the value 2. We can write this as {2}. The curly brackets indicate "set". It is possible to have a set of only 1 item inside.
The range is the set of y value outputs. In this case, the output is 2 because we have a horizontal line. No matter what the x input is, the output is always 2. This is known as a constant function. The output is constantly the same.
