The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
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Answer:
4.44
Step-by-step explanation:
the real answer is 4.44444444444
Each persons ticket costs $34.00(D)
all you have to do is subtract $6.80 from $142.80
then you divide the answer by 4
Answer:
0.034921 miles or 1843774 feet tall
Step-by-step explanation:
Using trigonometric functions we know that
and
where
=angle and r is the hypotenuse of the triangle.
First we will calculate the hypotenuse using the x equation, since we know x = 1 mile (distance from the building on the ground) we have:

Now we will calculate the height of the building using the y equation and so:

The building is 0.034921 miles or approximately 184.3774 feet tall.