Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer:
210
Step-by-step explanation:
1: Part/whole=%/100
2: 100-5=95
3: 3150/30=$105 uniforms.
Answer: $210
<em><u>Hope this helps.</u></em>
Arc NST is waay larger actually
And it's the largest
Volume = area * height
330 in^3 = area * 3 in
(330 in^3)/(3 in) = area = 110 in^2
Answer:
406.153846 or about 406 feet per minute
Step-by-step explanation:
Start by converting the 13 minutes per mile to feet per minute by turning the mile into 5,280 feet. So you run 5,280 feet in 13 minutes. Then you divide 5,280 by 13 so you get the amount of feet per minute, hence about 406 feet per minute.
I didn't know if you needed an exact answer or to round so I gave you both :)