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Deffense [45]
3 years ago
11

The sailboat has 1 large sail and one small sail. The large sail is 24 feet tall. The base of the sail is 12 feet long. What is

the area of the large sail?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

The area of the large sail of the sailboat is 144 feet²  .

Step-by-step explanation:

Given as :

The measure height of the large sail = 24 feet

The measure of base of the sail = 12 feet

The area of the sail = A feet²

Now, <u>Since The sail of the sailboat is in the form of right angle triangle</u>

So, From The area right angle triangle

Area of right angle Triangle =  \frac{1}{2} × height × base

Area = \frac{1}{2} × height of the sail × base of sail

Or, A = \frac{1}{2} × 24 × 12

Or , A = \frac{288}{2}

∴  A = 144 feet²

So, the area of sail = 144 feet²

Hence The area of the large sail of the sailboat is 144 feet²  . Answer

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A water pail in your backyard has a small hole in it. You notice that it has drained a total of 0.5 liter in 4 days. What is the
deff fn [24]

Answer:

0.125 liters per day

Step-by-step explanation:

0.5/4=.125

3 0
3 years ago
The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and
NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120

Let's find h with the quadratic formula:

\fbox {Quadratic formula:}  \frac{-b\pm\sqrt{b^2-4ac}}{2a}

h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation  

\fbox {Pythagorean equation:} <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17

H = 17

If we decrease the base and the height by 2 centimeters, we have  

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3

H' \approx 14.3

So, the hypotenuse decreases H - H' \approx 17 - 14.3 = 2.7

3 0
3 years ago
((negatives and positives))<br>(-2) + (-15) - (-3)​
borishaifa [10]

Answer:

14

Step-by-step explanation:

(-2) + (-15) - (-3)​

~Simplify

-2 - 15 + 3

~Subtract

-17 + 3

~Add

-14

Best of Luck!

6 0
3 years ago
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What is 1.5% of 30? (please I have no idea and I need to know ASAP)
xxMikexx [17]

Answer:

30 x 1.5% = .45

Hope this helps<3

3 0
3 years ago
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PLS Help im sooo stuck on this question pls help and show your work and please dont put a nonsense answer
Snowcat [4.5K]

XY = xZ

85b + 83 = 91b - 283

Subtract 85b from both sides:

83 = 6b - 283

Add 283 to both sides:

6b = 366

Divide both sides by 6:

B = 61

Now replace b with 61 and solve for the length:

85(61) + 83

5185 + 83 = 5268

The length is 5,268

8 0
3 years ago
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