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Reil [10]
2 years ago
13

What is the equation of the line that goes through the points (5, 11) and (7,21)?

Mathematics
1 answer:
iragen [17]2 years ago
5 0

Answer:

y = 5x - 14

Step-by-step explanation:

First point coordinates

x₁

5

y₁

11

Second point coordinates

x₂

7

y₂

21

Result

Slope (m)

5

m = 10 / 2 = 5 / 1 = 5

Your function

The entered points belong to an increasing, linear function.

Equation: y = 5x - 14.

Hope i helped :)

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forsale [732]
4X+60=640
4X=640-60
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8 0
3 years ago
Two numbers have a difference of 0.7 and a sum of 1 . What are the numbers
Crank
First number is f
Second number is s
f-s=.7
f+s=1
Using elimination, you could solve this.
-1(f-s=.7); eliminate the first number.
-f+s= -.7
f+s=1
2s=.3
s=.15
Now find the second number by plugging it in:
.15+s=1
1-.15=.85
The numbers are .15 and .85.


5 0
3 years ago
Which expression is equivalent to the given expression? 17x−32x x(17−32) x(32−17) 17x(1−32) 17(x−32)
Mumz [18]
Answer would be x(17-32)
7 0
3 years ago
Please please help with this!!
BlackZzzverrR [31]

Answer: 115

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If f(x) is differentiable for the closed interval [−4, 0] such that f(−4) = 5 and f(0) = 9, then there exists a value c, −4 <
Pavel [41]
\bf \textit{mean value theorem}\\\\
f'(c)=\cfrac{f(b)-f(a)}{b-a}\qquad 
\begin{cases}
a=-4\\
b=0
\end{cases}\implies f'(c)=\cfrac{f(0)-f(-4)}{0-(-4)}
\\\\\\
f'(c)=\cfrac{9-5}{0+4}\implies f'(c)=\cfrac{4}{4}\implies f'(c)=1
4 0
3 years ago
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