Question

The displacement vector r=2i-j+3k is aligned to the same direction as the force (F) whose magnitude is F =20N Determine the comple description of the force F

Answer 1

Answer:

Step-by-step explanation:

Displacement vector R = 2i + j +  3k

Unit vector along displacement vector

= R / I R I

= ( 2i + j +  3k )  / √ ( 2² + 1² + 3² )

= ( 2i + j +  3k )  / √ 14

Now force F acts in the direction of this unit vector . It is magnitude of 20 N

So this vector can be represented by the following expression

F = 20 [  ( 2i + j +  3k )  / √ 14 ]

$F= \frac{20}{\sqrt{14} } \times ( 2i+j+3k)$