Answer:
- Average age of the employees in 2003 = 57.216
- Average age of the employees in 2009 = 59.184
Step-by-step explanation:
We are given the function A(s) as;
A(s) = 0.328*s + 50 where s = number of years since 1981; that is,
s = 0 for 1981 and s = 9 for 1990
A(s) = the average age of an employee
- Now, the average age of the employees in 2003, A(22) = 0.328*22 + 50
Here s = 22 because 2003 - 1981 = 22 years
Therefore, average age of the employees in 2003 = 7.216 + 50 = 57.216 .
- Average age of the employees in 2009, A(28) = 0.328*28 + 50
Here, s = 28 because 2009 - 1981 = 28 years
Therefore, average age of the employees in 2009 = 9.184 + 50 = 59.184 .
Answer:
y=2x+1
Step-by-step explanation:
y=mx+b
-5=2(-3)+b
-5=-6+b
1=b
Plug it in to get y=2x+1
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)
Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9.
Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27
Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45
Final Answer: 45 square units
note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
There's about 22 because if you extend it by going 3+1 and so on it wont hit 90 exactly but it'll be 91, so 22 small sliced pizzas and 23 large sliced pizzas