The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is
So the desired probability is
Consider the expression below.
2 answers:
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The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is
So the desired probability is
Answer:
The ratio of AC/CB=1/3
Step-by-step explanation:
We use the section formula:
We substitute the point A(-1.5,0) and B(4.5,8).
We plug in the points to get:
This is supposed to be equal to: (0,2).
We can equate, corresponding coordinates to find m and n.
This implies that:
Therefore the ratio is m:n=1:3
Answer:
<h2>D</h2>Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about</h3>- inequality
- algebra
- PEMDAS
first note: it will be more easy if we solve the inequality first
so let's solve it together
so what we get
we get that x is greater than 12
<h2>so the answer would be d</h2>